# Java Program to Check Disarium number

Write a simple java program to verify if a given number is disarium number or not.

## 1. Disarium number

A number is called DISARIUM if sum of its digits, powered with their respective position, is equal to the original number.

For example, consider following numbers.

11 + 32 + 53 = 1 + 9 + 125 = 135

81 + 92 = 8 + 81 = 89

11 + 72 + 53 = 1 + 49 + 125 = 175

51 + 12 + 83 = 5 + 1 + 512 = 518

## 2. Java Program to find Disarium number

```public class Main
{
public static void main(String[] args) {

System.out.println("134 is disarium number " + isDisarium(134));
System.out.println("135 is disarium number " + isDisarium(135));
System.out.println("136 is disarium number " + isDisarium(136));
}

static boolean isDisarium(int originalNumber)
{
//Total number of digits
int numberOfDigits = Integer.toString(originalNumber).length();

int sumOfDigits = 0; // Initialize sum of terms
int tempNum = originalNumber;
while (tempNum!=0)
{
// Get the rightmost digit
int currentDigit = tempNum % 10;

// powering according to the positions and adding to sumOfDigits
sumOfDigits = (int) (sumOfDigits + Math.pow(currentDigit, numberOfDigits--));
tempNum = tempNum/10;
}

// If sum is same as number, then number is
return (sumOfDigits == originalNumber);
}
}
```

Program output.

```134 is disarium number false
135 is disarium number true
136 is disarium number false
```

Happy Learning !!